Calculate the molar solubility of silver chloride (AgCl) in:

Question

a-deionized water and
b-.20M NaCl solution
Given Ksp=1.6*10^-10

Answer 1

.........AgCl ==> Ag^+ + Cl^-
I........solid....0.......0
C........-x.......x.......x
E........solid....x.......x

Ksp = 16E-10 =- (Ag^+)(Cl^-)
Substitute and solve for x = (AgCl) in M.

for part B. You need to calculate (or find in a table) the activity of 0.20M NaCl solution and recalculate the solubility using activities instead of molarity..