.........MgCO3 ==>Mg^2+ + CO3^2-
I........solid....0.......0.0017
C.......for x.....x.........x
E.......solid.....x.........x+0.0017
6.82E-6 = (x)(0.0017+x)
Solve for x = solubility in mols/L.
Calculate the molar solubility of MgCO3 in a solution that already contains 1.7×10−3 M sodium carbonate.
MgCO3 Ksp = 6.82 x 10-6
IMPORTANT NOTE: You must use the quadratic equation to solve this problem.
(DrBob222- thank you so much for all your help!)
1 answer
1 answer