Calculate the molar solubility of Ag2SO4 when dissolved in water (Ksp = 1.8 x 10-5)

Answer 1

...................Ag2SO4 ==> 2Ag^+ + SO4^2-
I...................solid...............0...................0
C..................solid...............2x.................x
E..................solid................2x.................x

Ksp = (Ag^+)^2(SO4^2-)
Substitute the E line into the Ksp expression and solve for x. x is the solubility of Ag2SO4. Post your work if you get stuck.

Answer 2

0.0235