pOH = 14 - pH
therefore, ur pOH will be = 14 - 4.53
= X (suppose)
pOH = -log[OH^-]
X = -log[OH^-]
Solve for [OH^-]
calculate the molar hydroxide ion concentration of each of the following solutions given the pH 4.53. Answer should be for OH-.
Please show me how to do this in step by step
3 answers
OH=9.47
-log= 0.976349979
is this correct
-log= 0.976349979
is this correct
okay correct.....so the 9.47 is correct...then you put in your calculator -9.47 2nd log to get 3.388441561 -10, which is rounded off to 3.4 * 10^-10