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Calculate the molar enthalpy of solidification when 10.00KJ of energy are lost as 30.00g water are frozen at 0*C.

i divided 30/18.02 =1.664 mol
then, divided 10KJ/1.664mol =6.010 KJ/mol

Am i correct?
Thank you!

1 answer

That looks right to me although I call it latent heat of fusion.

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