Calculate the Molar Enthalpy of Neutralization in kJ/mol of the reaction between a monoprotic acid and a monoprotic base, given the following information: *Make sure you report your answer using the correct sign*
The temperature change equals 9.80 degrees C, 50.0mL of 1.00 M concentrationof Acid
50.0mL of 1.00 M concentration of Base, heat capacity of the calorimeter is 6.50 J/degree C. The specific heat of
water is 4.180 J/g degree C.
3 answers