Calculate the molality of of a sol'n whose density is 1.15 g/ml
3 answers
Is this a problem you made up or a homework question from class or your text?
oh I'm sorry it's a typo
The question is this:
Calculate the molality of a 0.410 molar aqueous glucose solution whose density is 1.15 g/mol
The question is this:
Calculate the molality of a 0.410 molar aqueous glucose solution whose density is 1.15 g/mol
0.410 M glucose means 0.410 mols glucose/L soln. The molar mass of glucose is approximately 180 g/mol which means 0.410 is 0.410 x 180 = about 74g. (You need to go through all of these estimates and use better values.)
The mass of 1000 mL of the soln is
1.15 g/mL x 1000 = 1150 g which means the mass of the solvent is 1150-74 = ?. Then m = mols/kg solvent.
The mass of 1000 mL of the soln is
1.15 g/mL x 1000 = 1150 g which means the mass of the solvent is 1150-74 = ?. Then m = mols/kg solvent.
1 answer