Calculate the molality of aqueous solution of sulfuric acid by the following data

Question

Molarity =18
Molar mass =98
Density =1.84 g/cm3

Answer 1

First, we need to calculate the molality of the sulfuric acid solution using the formula:

Molality (m) = (Molarity * Molar Mass) / (1000 * Density)

Given data:
Molarity = 18 M
Molar Mass = 98 g/mol
Density = 1.84 g/cm^3

Converting density to g/mL:
Density = 1.84 g/cm^3 = 1.84 g/mL

Now, plug the values into the formula:

Molality (m) = (18 * 98) / (1000 * 1.84)
Molality (m) = (1764) / (1840)
Molality (m) = 0.96 mol/kg

Therefore, the molality of the aqueous solution of sulfuric acid is 0.96 mol/kg.