calculate the molality of a solution that has 1.02kg sucrose C12H22O11 dissolved in 554g water?

Answer 1

mols sucrose = grams/molar mass = ?
Then m = mols/kg H2O

Answer 2

molality=molesSolute/kgsolvent
= (1020/molmassSucrose)/.554

in my head, on the order of m=7