Calculate the molality of 6.00 M H2SO4 solution. The density of the solution is 1.34 g/mL.

Answer 1

6.00 M is 6.00 moles/L of soln.
That is 6 moles x (98 g/mol) = 588 grams H2SO4 in the liter of soln..
Take 1 L of the solution. That will have a mass of volume x density = 1000 mL x 1.34 g/mL = 1340 grams. How much is H2SO4 and how much water. There are 588 grams H2SO4; therefore, 1340 g-588 = 752 g H2O.
molality = mols/kg solvent. You know moles H2SO4. You know kg solvent. You finish.

Answer 2

7.98?

Answer 3

Yes, but check all my math leading up to that last step.