Calculate the molality, molarity, and mole fraction of FeCl3 in a 39.2 mass % aqueous solution (d = 1.238 g/mL).

Answer 1

m = mols/kg solvent
M = mols/L soln
X = n of X/total mols.

39.2 mass% means 39.2 g FeCl3 per 100 g solution.
mols FeCl3 = 39.2g/molar mass
Use density to convert 100 g to volume in mL, convert to L, and mols/L = M

You try the others. Just use the definition to go from unit to unit.