Calculate the maximum height using the initial speed, half-time, and angle. The initial speeed is 18m/s, half time is 1.8, and the angle is 75. And how is this written out to solve.

Answer 1

Max height H is given by

2gH = (Vo sin A)^2

You don't need the half-time, T, if you know g.

Vo sin A = g T
g = Vo sinA /T

2 Vo sin A*H/T = (Vo sin A)^2

H = Vo sinA*T/2

in other words, the average vertical velocity component multiplied by the half-time.