Calculate the maximum height a ball of mass 1.2 kilograms will attend if projected vertically upwards with an initial velocity of 17 m/s

Answer 1

time to peak (t) ... 17 m/s / 9.8 m/s^2

average velocity during ascent ... (17 m/s + 0 m/s) / 2

max height = (time to peak) * (average ascent velocity)