To calculate the mass of zinc that will produce 35.8g of zinc trioxonitrate(V) (Zn(NO3)2), we need to determine the molar ratio between zinc and zinc trioxonitrate(V) in the balanced equation.
From the balanced equation:
3 moles of zinc (Zn) produce 1 mole of zinc trioxonitrate(V) (Zn(NO3)2)
We know the molar mass of Zn(NO3)2:
Molar mass of Zn(NO3)2 = (1 x atomic mass of Zn) + (2 x atomic mass of N) + (6 x atomic mass of O)
= (1 x 65.38 g/mol) + (2 x 14.01 g/mol) + (6 x 16.00 g/mol)
= 65.38 g/mol + 28.02 g/mol + 96.00 g/mol
= 189.40 g/mol
Now, we can calculate the moles of Zn(NO3)2:
moles of Zn(NO3)2 = mass of Zn(NO3)2 / molar mass of Zn(NO3)2
= 35.8 g / 189.40 g/mol
≈ 0.1892 mol
Since the molar ratio between zinc (Zn) and zinc trioxonitrate(V) (Zn(NO3)2) is 3:1, we can determine the moles of zinc:
moles of Zn = moles of Zn(NO3)2 x 3
= 0.1892 mol x 3
≈ 0.5676 mol
Finally, we can calculate the mass of zinc:
mass of Zn = moles of Zn x molar mass of Zn
= 0.5676 mol x 65.38 g/mol
≈ 37.1 g
Therefore, the mass of zinc that will produce 35.8g of zinc trioxonitrate(V) is approximately 37.1 grams.
calculate the mass of zinc that will produce 35.8g of zinc trioxonitrate(V) 3Zn +8HNO3➡️ 3Zn(NO3)2 +4H2O + 2NO
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