Calculate the mass of water produced from the reaction of 24.0 g of H2 and 160.0 g of O2. What is the limiting reagent?

Answer 1

1. Write the equation and balance it.
2. Convert 24.0 g H2 and 160 g O2 to moles. moles = grams/molar mass.
3a. Using the coefficients in the balanced equation, convert moles H2 to moles H2O.
3b. Do the same for moles O2 to moles H2O.
3c. You have two different answers for moles of the product. Obviously, one of them is correct and one is not. The correct one, in limiting reagent problems. is ALWAYS the smaller one and the reactant giving that number is the limiting reagent.

4. Using the smaller value in 3c, convert to grams. grams = moles x molar mass.
Post your work if you get stuck.

Answer 2

180g H2O ; Oxygen