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calculate the mass of solid NaCl that must be added to 1.5L of 0.100M AgNO3 solution to precipitate all the Ag+ ions in the form of AgCl?

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AgNO3 + NaCl ==> AgCl + NaNO3
moles AgNO3 = M x L = ?
moles NaCl = moles AgNO3
grams NaCl = moles NaCl x molar mass NaCl

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8.78g

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