Coulombs = amperes x seconds
C = 2.6 A x 70 min x (60 sec/min) = ? (about 11,000 but you should be more accurate than that).
You know that 96,500 coulombs will deposit 108 grams Ag metal; therefore, 11,000 coulombs will deposit 108 x (11,000/96,500) = ? g Ag metal.
Calculate the mass of silver depostited when a current of 2.6 amperes is passed through a solution of it for 70minutes [1 faraday=96500C,Ag 108]
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