calculate the mass of copper deposited when a current of 0.5

Question

amphere was passed through a solution of copper (ii) chloride for 45 minutes in an electrolytic cell (eu=63.IF=96500C)

Answer 1

Coulombs = amperes x seconds
C = 0.5 x 45 x (60 sec/min) = 1350
96,500 coulombs will deposit 63.54/2 = 31.77 g Cu
63.54 g x (1350/96,500) = ? g Cu deposited.

Answer 2

0.89