Calculate the mass in grams of the undiluted bleach that was in the sample of bleach titrated.

Question

Given:
Density of undiluted bleach unkown is 1.042 g/mL.
14.44 mL of .100 M Na2S2O3.
.0537 grams of NaClO.
Each sample should conain 1/5 of the original undiluted bleach. Since 5mL of undiluted bleach wee originally used, each titration sample contains 1/5 of the 5.00 mL. Use density to convert the volume of a titration sample into grams.
Please help.

Answer 1

I'm not sure I have followed the question completely but here is what I think.
volume is 5.00 mL and you take 1/5 that or 1.00 mL.
The initial 5.00 mL contains 5.00 mL x 1.042 g/mL = 5.20 grams. If you take 1.00 mL of that each mL will contain 5.20/5.00 = 1.042 grams.
You get the same number if you used just 1.00 mL from 1.00 mL x 1.042 g/mL = 1.042grams.