calculate the mass and volume of oxygen released when 29;4g potassium chlorate decomposes to form potassium chloride and oxygen

Answer 1

The equation is
2KClO3 ==> 2KCl + 3O2

This is done the same way as the SO2 problem. Just follow the steps to obtain the mass of O2.
Do you want that volume at STP? I assume so. Remember that 1 mol of any gas occupies 22.4 L. You know how many mols O2 you have. mols O2 x (22.4L/mol) = ?L

Answer 2

7,16

Answer 3

44.8L

Answer 4

How to calculate the volume and mass of oxygen realesead when 29.4g potassium chlorate decomposes to form potassium chloride and oxygen

Answer 5

how do we calculate the mass and volume of oxygen released when 29,4 g potassium chlorate decomposes to form chloride and oxygen??

Answer 6

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