calculate the mass and volume of oxygen released when 29;4g potassium chlorate decomposes to form potassium chloride and oxygen

6 answers

The equation is
2KClO3 ==> 2KCl + 3O2

This is done the same way as the SO2 problem. Just follow the steps to obtain the mass of O2.
Do you want that volume at STP? I assume so. Remember that 1 mol of any gas occupies 22.4 L. You know how many mols O2 you have. mols O2 x (22.4L/mol) = ?L
7,16
44.8L
How to calculate the volume and mass of oxygen realesead when 29.4g potassium chlorate decomposes to form potassium chloride and oxygen
how do we calculate the mass and volume of oxygen released when 29,4 g potassium chlorate decomposes to form chloride and oxygen??
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