Calculate the magnitude of the net electrostatic force on charge q1 due to the charges q2 and q3.

IF
q1= 3μ
distances from q1 to q2 is =0.10m
q2=-5μ
distances from q1 to q3 is =-0.15m
q3=-2μ
In simple steps

1 answer

The formula to calculate the magnitude of the net electrostatic force between two charges q1 and q2 is given by Coulomb's Law:

F = k * |q1 * q2| / r^2

Where:
- F is the magnitude of the force
- k is Coulomb's constant, approximately 9 x 10^9 N*m^2/C^2
- q1 and q2 are the charges
- r is the distance between the two charges

For the force between charges q1 and q2:
F1 = (9 x 10^9 N*m^2/C^2) * |(3μC) * (-5μC)| / (0.10m)^2

Simplifying:
F1 = (9 x 10^9 N*m^2/C^2) * (15 x 10^-6 C^2) / (0.01m^2)
F1 = (9 x 10^9 N*m^2/C^2) * (1.5 x 10^-5 C^2) / (0.0001m^2)
F1 = (9 x 10^9 N*m^2/C^2) * (1.5 x 10^-1 N)
F1 = 1.35 x 10^9 N

For the force between charges q1 and q3:
F2 = (9 x 10^9 N*m^2/C^2) * |(3μC) * (-2μC)| / (0.15m)^2

Simplifying:
F2 = (9 x 10^9 N*m^2/C^2) * (6 x 10^-6 C^2) / (0.0225m^2)
F2 = (9 x 10^9 N*m^2/C^2) * (0.2666667 x 10^-4 C^2 / 0.0225)
F2 = (9 x 10^9 N*m^2/C^2) * (2.66667 x 10^-2 N)
F2 = 2.4 x 10^8 N

The net electrostatic force on charge q1 due to charges q2 and q3 is the vector sum of the two forces F1 and F2:

Net Force = F1 + F2
Net Force = 1.35 x 10^9 N + 2.4 x 10^8 N
Net Force = 1.59 x 10^9 N

Therefore, the magnitude of the net electrostatic force on charge q1 due to charges q2 and q3 is 1.59 x 10^9 N.