The answer I found is -2269.1 kj/mol
Is this right or did I make a mistake
Calculate the lattice energy in kJ/mol for CaCl2 from the following information: Energy needed to vaporize one mole of Ca(s) is 192kJ. For calcium the first ionization energy is 589.5kJ/mol and the second ionization energy is 1146kJ/mol.
The electron affinity of Cl is -348kJ/mol.
The bond energy of Cl2 is 242.6kJ/mol of Cl-Cl bonds.
The standard heat of formation of CaCl2 is -795kJ/mol
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