mols Ag2SO4 = grams/molar mass - ? and that is the M since it is in 1 L. I estimate that to be 0.015 M
........Ag2SO4 <--> 2Ag^+ + SO4^2
I.......solid........0.......0
C.......solid........2x......x
E.......solid........2x......x
Substitute the E line into the Ksp expression and solve for Ksp.
Calculate the Ksp for silver sulfate if the solubility of Ag2SO4 in pure water is 4.5 g/L.
Ag2SO4(s) <--> 2Ag^+(aq) + SO4^2-(aq)
1 answer
1 answer