mols HCOOH = grams/molar mass, then
M = mols/L soln. I get about 0.05M but you should confirm that.
.........HCOOH + H2O ==> H3O^+ + HCOO^-
I .......0.05..............0.......0
C.......-0.003.........0.003..0.003
E...0.05-0.003.........0.003...0.003
Substitute from the ICE chart above into the IKa expression and solve for Ka.
Calculate the KA of formic acid if 2.3 g of it is dissolved in 1 litre of water to give [H+] of 0.003 M.
1 answer
1 answer