The internal energy, ΔU, can be calculated using the following equation:
ΔU = ΔH - PΔV
where ΔH is the change in enthalpy, P is the pressure, and ΔV is the change in volume. At constant pressure, ΔV is equal to the initial volume, which is 1.0 m3. Plugging in the values:
ΔU = -899 J - (40 Pa)(1.0 m3)
ΔU = -899 J - 40 J
ΔU = -939 J
Therefore, the internal energy change for the reaction is -939 J.
Calculate the internal energy for the reaction shown below which was performed at constant pressure of 40 Pa and a volume of 1.0 m3.
N2 +3H2→ 2 NH3 ΔH = -899 J
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