Calculate the hydronium ion consentration and the hydroxide concentration in blood in which the PH is 7.3.

Hydronium = [H3O+] = 10-pH or [H3O+] = antilog (- pH)

and I got 1.00 x 10^7.3 for both concentrations is this correct?

ABsolutely silly. You did not do the math.

PUt this in your calculator
INVlog (-7.3)

Then, find the concentration of the OH by concentrationH+ * concentrationOH=1E-14

I can check your work if you need. You need to use a calculator on these.

I did do the math with my calculator, maybe the wrong math but I followed instructions on a website and did what I thought was right.
pOH = - log [OH-]

I don't have INVlog on my calculator I have log but that's it.

3 answers

OH-=10^(-pOH)

7.3

Using the formula [H3O+] = 10-pH, we get:

[H3O+] = 10-7.3

[H3O+] = 5.01 x 10^-8 mol/L

To find the concentration of the OH- ions, we use the formula concentrationH+ * concentrationOH-=1E-14:

[OH-] = 1E-14/[H3O+]

[OH-] = 1E-14/(5.01 x 10^-8)

[OH-] = 1.99 x 10^-7 mol/L

Therefore, the hydronium ion concentration in blood with a pH of 7.3 is 5.01 x 10^-8 mol/L and the hydroxide ion concentration is 1.99 x 10^-7 mol/L.