m g h = 334*10^3 joules/kg * m
h = 334*10^3/9.81 in meters
Calculate the height from which a block of ice at zero degrees celcius nust be dropped for it to completely melt upon impact. Assume that there is no air resistance and that all the energy goes into melting the ice.
2 answers
0°c ice converted to 0°c water
mlf=m×3.36×10^5
Work done=heat produced
or,mgh=mlf
or,gh=lf
or,h=3.36×10^5÷9.8
or,h=34.286×10^3
mlf=m×3.36×10^5
Work done=heat produced
or,mgh=mlf
or,gh=lf
or,h=3.36×10^5÷9.8
or,h=34.286×10^3