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Calculate the heat absorbed when 46.0 g of ice at -10.0°C is converted to liquid water at 85.0 °C. The specific heat of ice is 2.03 J/g °C, the molar heat of fusion of ice is 6010 J/mol, and the specific heat of water is 4.18 J/g °C.

The heat is calculated by considering the three-step process of warming ice from -10.0 °C to 0.0 °C, melting the ice, and heating liquid water to 85.0 °C

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