Calculate the ∆H°rxn for the combustion of methane using the given ∆H°f.

Question

CH4 (g) + 2 O2 (g) → CO2 (g) + 2H2O (g)

∆H°f, methane(g) = -74.60 kJ/mol

∆H°f, water(l) = -285.8 kJ/mol

∆H°f, carbon dioxide(g) = -393.5 kJ/mol

Answer 1

dHrxn = (n*dHo products) - (n*dHo reactants)
Substitute the numbers and calculate. Post your work if you get stuck.