first: OH=.1M
pOH=-logOH=1
PH=14-pOH=13
H*OH=10^-14
H=1/10 * 10^-14=10^-13
Calculate the H+ of 0.1 M NaOH
Calculate the pH of 0.1 M NaOH
[H+]=10^ph
[H+]=10^-13
[H+]=1*10^-13M
Since pH+ pOH=14
pH= -log (0.1M)
pH=1
so 14-1
pH= 13
2 answers
Surely you meant for one of those lines to read pOH. I don't follow your work but the bottom line is right.
If yu have 0.1M NaOH, then OH = 0.1, pOH is 1, which makes pH = 13. In that first line it should be (H^+) = 10^-pH
If yu have 0.1M NaOH, then OH = 0.1, pOH is 1, which makes pH = 13. In that first line it should be (H^+) = 10^-pH
2 answers