3.7% KCl = 3.7 g KCl/100 g soln =
3.7 g KCl/(3.7 g KCl + 96.3 g H2O) =
Convert 3.7 g KCl to moles. moles = grams/molar mass
Then molality = moles/kg solvent.
delta T = i*kf*m
i = 2, kf you know and m from above.
Calculate the freezing point of the following solutions, assuming complete dissociation.3.7% KCL by mass (in water)
1 answer