calculate the freezing point of an aqueous solution containing 10.50 g of MgBr2 in 200 g of water (MgBr2=184 g, Kf for water =1.80 K kg mol-1)

Answer 1

W2=10.50g, W1=200g, molar mass of mgbr2(M2) =184g dtf=1000×kf×w2/w1×M2 dtf=1000×1.86×10.50/200×184 dtf=19.530/200×184=0.53 now, tf=t0-dtf tf=273-0.53 tf=272.47K

Answer 2

can we multiply with i