delta T = i*Kf*m and I assume all of the solutions you have are non-electrolytes and i = 1.
You know Kf (the freezing point constant) and if you don't it will be in your text and it's all over the web. m is the molality and that's in the problem (in this case 1.40). Calculate delta T and subtract that from the normal freezing point of water which is 0 C..
Calculate the freezing point of a water solution at each concentration.
1.40m?
What are the steps to calculate this?
3 answers
So would it be
Delta T = i*Kf(0 degrees C)*1.40
Delta T/Kf *1.40v= i?
Delta T = i*Kf(0 degrees C)*1.40
Delta T/Kf *1.40v= i?
No. In trying to avoid confusing you because I didn't know what other compounds you had (and some may have been ionic), I ended up confusing you by including the i. Just forget the i or if yu want to keep it there, note that I TOLD you it was 1 for this problem.
delta T = Kf*m
Did you look up Kf? Evidently not. Kf is the freezing point constant for H2O and has a value of 1.86, i = 1. m = 1.40 from the problem.
delta T = 1*1.86*1.40.
Find delta T and subtract from zero to find the new freezing point.
delta T = Kf*m
Did you look up Kf? Evidently not. Kf is the freezing point constant for H2O and has a value of 1.86, i = 1. m = 1.40 from the problem.
delta T = 1*1.86*1.40.
Find delta T and subtract from zero to find the new freezing point.
1 answer