The force consists of two parts (with buoyancy neglected)
(1) The weight, (4/3)*pi*R^3*(density)
(2) The drag force, (0.95 kg/s)*V
Look up the density of copper and use SI units for R and V. Add the two components for the answer in Newtons.
Calculate the force required to pull a copper ball of radius 2.00 cm upward through a fluid at the constant speed 9.00 cm/s. Take the drag force to be proportional to the speed, with proportionality constant 0.950 kg/s. Ignore the buoyant force
1 answer
1 answer