The heat of fusion of ice is 79.8 cal/deg C.
Let T = final temperature, and sum heat change = 0
8 kg (T-20) + 2 kg ((T-0)+(79.8))=0 cal-kg
Solve for T to get T=+0.04 deg. C.
Calculate the final temperature. Two kg ice at zerodegree celsius is mixed with 8 kg of water at 20 degree celsius.
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