Calculate the final temperature that results from mixing 245 grams of cobalt, specific heat 0.446 J/g0C, at 1420C with 106 grams of water at 24.80C.

Answer 1

heat needed to raise water to 100C:
.106*4.18*(100-24.8)=.331Kj
heat needed to change water to steam: 2264.76kJ/kg*.106= 240kj
Heat needed to raise steam from 100 to Tf.
.106*2kj/kg*(Tf-100)=???

Now, heat given off by cooling Cobalt:
.245*.446*(tf-1460)
sume of heats = 0
.245*.446*(tf-1460)-240-.106*2kj/kg*(Tf-100)-.331=0
solve for Tf check my work. Tf has to be above 100C, or the steam assumption was wrong.

Answer 2

bobpursley is incorrect