Calculate the final temperature if 50 kg of iron is heated from 15.0°C with 5000 kJ of heat. The molar heat capacity of iron is 25.08 J mol–1 K–1.
2 answers
5E6J = mass Fe x specific heat Fe x (Tfinal-Tinitial)
Thanks!
Here's my answer, but I don;t know if it is correct:
5000KJ=50,000g/55.85 g/mol*25.08j/ mol k *(T high-15C);
5000kj=22452.99 (T high-15C);
(T high-15C)=5000kj/22452.99J mol–1 K–1/1000,
T high-15C=222.69, T high=22.69+15=238C
Here's my answer, but I don;t know if it is correct:
5000KJ=50,000g/55.85 g/mol*25.08j/ mol k *(T high-15C);
5000kj=22452.99 (T high-15C);
(T high-15C)=5000kj/22452.99J mol–1 K–1/1000,
T high-15C=222.69, T high=22.69+15=238C