Calculate the final concentration (mol.dm-3) when a 0,6 mol.dm-3 solution of H2SO4 of volume 250 cm3 is mixed with another H2SO4 solution of concentration 0,3 mol.dm-3 and volume 200 cm3.

Answer 1

To calculate the final concentration of the mixture, we can use the formula:

C1 V1 + C2 V2 = Cfinal Vfinal

Where:
C1 = initial concentration of the first solution (0,6 mol.dm-3)
V1 = volume of the first solution (250 cm3)
C2 = initial concentration of the second solution (0,3 mol.dm-3)
V2 = volume of the second solution (200 cm3)
Cfinal = final concentration of the mixture (what we are trying to find)
Vfinal = total volume of the mixture (250 cm3 + 200 cm3 = 450 cm3)

Now we can substitute the values into the formula:

(0,6 mol.dm-3)(250 cm3) + (0,3 mol.dm-3)(200 cm3) = Cfinal (450 cm3)

150 mol + 60 mol = Cfinal (450 cm3)

210 mol = Cfinal (450 cm3)

Cfinal = 210 mol / 450 cm3
Cfinal ≈ 0,47 mol.dm-3

Therefore, the final concentration of the mixture will be approximately 0,47 mol.dm-3.