Calculate the final centigrade temperature required to change 20 litres of gas at 120°C and 1 atmosphere to 25 litres at 2 atmosphere.

8 answers

PV=kT, so PV/T is constant
You want T such that

2*25/(T+273) = 1*20/(120+273)
the answer does no correspond
ond with the one on the textbook
What's the answer to the question?
Busola
Pls what's the answer?
Busola
The answer in the text book is 23 degree celcius and I don't seem to be getting it with ur formula.
Pls work out the question
I don't get it
Calculate the final centigrade temperature required to change 20 litres of gas at 120°C and 1 atmosphere to 25 litres at 2 atmospheres.

Pressure × Volume / Temperature = Number of molecules
PV / T = N
Convert 120°C to 393.15°K

Original state:
1 atmosphere × 20 Liters / 393.15°K = N moles

Final state:
2 atmosphere × 25 Liters / T°K = N moles (solve for T)

Since N remains constant, we can combine the two statements:
1 × 20 / 393.15 = 2 × 25 / T

Solution:
20 / 393.15 = 50 / T
0.05087116877 = 50 / T
T × 0.05087116877 = 50
T = 50 / 0.05087116877
T = 982.875°K
T = 709.725°C