Calculate the equilibrium concentration of each compound if 0.340 moles of HI are placed in a 5.90 liter container at 520°C. Kc = 0.170 for the reaction at this temperature.
soo i tried doing this by setting up an ICE table
and finding what x equaled buuuut it didn't work..
please help! thanks
3 answers
The ICE table should work. Post your work and I'll find your error.
sorry it was for this problem
Calculate the equilibrium concentration of each compound if 2.10 moles of CO2 and 3.70 moles of H2 are placed in a 2.90 liter container at 300°C. Kc = 1.90 for the reaction at this temperature.
okay so i did
CO2(g) + H2(g) = CO(g) + H2O(g)
.724-x..1.276-x......+x......+x
x^2/(.724-x)(1.276-x) =1.9
and i have
Quad form:
A=.9
B=-3.8
C=1.75522
Answer: 3.694=x
Calculate the equilibrium concentration of each compound if 2.10 moles of CO2 and 3.70 moles of H2 are placed in a 2.90 liter container at 300°C. Kc = 1.90 for the reaction at this temperature.
okay so i did
CO2(g) + H2(g) = CO(g) + H2O(g)
.724-x..1.276-x......+x......+x
x^2/(.724-x)(1.276-x) =1.9
and i have
Quad form:
A=.9
B=-3.8
C=1.75522
Answer: 3.694=x
I get the same answer and the coefficients are the same as yours for one root but 3.69 cant be correct because you had only 0.724 initially. For the other root I calculated 0.528 but I didn't check my figures. That should be the answer to the problem. Check me out on that.