Calculate the enthalpy change in the reaction of H2 with F2 to produce HF. The H–H and F–F bond energies are 436 and 155 kJ/mol, respectively, and the H–F bond energy is 567 kJ/mol

H2 (g) + F2 (g) --> 2HF (g)

2 answers

Ooops did not mean to post this twice!
dHrxn = (n*BE reactants) - (n*BE products)
BE = bond energy.