A. heat to move ice from -4.00 to zero C.
q = mass ice x specific heat ice x (Tfinal-Tinitial)
B. heat to melt ice at zero C to liquid water at zero C.
q = mass ice x heat fusion.
C. heat to move liquid water from zero C to 100 C.
q = mass water x specific heat H2O x (Tfinal-Tinitial)
D. heat to convert H2O @ 100 C to steam @ 100 C.
q = mass water x heat vaporization
E. heat to move steam @ 100 C to 109 C.
q = mass steam x specific heat steam x (Tfinal-Tinitial)
Total q = delta H = q1 + q2 + q3 + q4 + q5.
Note that specific heats are given in J/g*K but heat fusion and heat vaporization are given in kJ/mol. I would suggest you change kJ/mol to J/g so as to keep all of the units the same.
Post your work if you get stuck. I'll check your answer and your work but only if you show your work.
Calculate the enthalpy change (in kJ) associated with the conversion of 25.0 grams of ice at -4.00 °C to water vapor at 109.0 °C.
The specific heats of ice, water, and steam are 2.09 J/g-K, 4.18 J/g-K, and 1.84 J/g-K, respectively.
For H2O, ΔHfus = 6.01 kJ/mol and ΔHvap = 40.67 kJ/mol.
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