Calculate the enthalpy change, ÄH DeltaH, for the process in which 12.7g g of water is converted from liquid at 7.3 ∘ C \, ^\circ C to vapor at 25.0 ∘ C \, ^\circ C .

Question

Calculate the enthalpy change, ÄH DeltaH, for the process in which 12.7g g of water is converted from liquid at 7.3 ∘ C \, ^\circ C to vapor at 25.0 ∘ C \, ^\circ C . 
For water, ÄH vap  \Delta H_{\rm vap} = 44.0kJ/mol kJ/mol at 25.0 ∘ C \, ^\circ C and s s = 4.18J/(g⋅ ∘ C) J/(g\cdot{ ^\circ C}) for H 2 O(l)

DrBob222 · Answer

dH for H2O moving from 7.3C to 25C is dH = mass H2O x specific heat H2O x (Tfinal-Tinitial) dH for vaporization at 25C is dH = mass H2O x Hvap. Add the two together for the total.