dHf = delta H formation
dHf rxn = (n*dHf products) - (n*dHf reactants)
calculate the enthalpy change for: (enthalpy of formation of aqueous sodium hydroxide is -469.60 kJ/mol. enthalpy of formation of liquid water is -285.8 kJ/mol) 2Na + 2H2O = 2 NaOH + H2
1 answer
1 answer