the molar mass of water is 18.0 g
E = [25 * (100 - 25) * .00418] +
... [(25 / 18) * 40.6]
Calculate the energy (in kJ) required to heat 25 g of liquid water from 25oC to 100.oC and change it to steam at 100oC. The specific heat capacity of liquid water is 4.18 J/goC, and the molar heat of vaporization of water is 40.6 kJ/mol.
1 answer