Calculate the empirical formula of Tylenol: C, 63.56%; H, 6.00%; N, 9.27%; O, 21.17%

Question

Olereb48 · Accepted Answer

Follow the sequence:
% => gms => moles => reduce moles (divide by smallest mole value) => Emp. Ratio => C:H:N:O

C: 63.56% => 63.56g/12g/mol = 5.297mol
H: 6.00% => 6.00g/ 1g/mol = 6.000mol
N: 9.27% => 9.27g/14g/mol = 0.662mol
O: 21.17% => 21.17g/16g/mol = 1.323mol

N:H:N:O Emp Ratio =>
5.297 6.000 0.662 1.323
_____ : _____ : _____ : _____
0.662 0.662 0.662 0.662

=> 8:9:1:2 Empirical Ratio

=> C8H9NO2

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