Calculate the eccentricity for the planet of the distance between foci is 5,000,000 km and the distance of the major axis is 299,000,000 km

a) 0.0167
b) 0.598
c) 59.8
d) 0.167

1 answer

recall that e = c/a. So, ignoring all those trailing zeroes, e = 5/299

technically, that's (2c)/(2a) but it still works out the same
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