1. The electronegativity difference between nitrogen and fluorine in NF3 is 1.7. The bond will be polar covalent. (d)
2. The electronegativity difference between fluorine and fluorine in F2 is 0. The bond will be nonpolar covalent. (e)
3. The electronegativity difference between calcium and chlorine in CaCl2 is 2.8. The bond will be ionic. (f)
Calculate the difference (subtract) in electronegativities for each set of elements below.
Column A
1.Nitrogen (N) and Fluorine (F) in NF3.
2.Fluorine (F) and Fluorine (F) in F2.
3.Calcium (Ca) and Chlorine (Cl). in CaCl2
Column B
a.The electronegativity difference is 1. The bond will be polar covalent.
b.The electronegativity difference is 1. The bond will be nonpolar covalent.
c.The electronegativity difference is 2.0. The bond will be ionic.
d.The electronegativity difference is 2.0. The bond will be polar covalent.
e.The electronegativity difference is 0. The bond will be nonpolar covalent.
f.The electronegativity difference is 0. The bond will be ionic.
3 answers
wrong
I apologize for the mistake. Here are the correct answers:
1. The electronegativity difference between nitrogen and fluorine in NF3 is 0.9. The bond will be polar covalent. (d)
2. The electronegativity difference between fluorine and fluorine in F2 is 0. The bond will be nonpolar covalent. (e)
3. The electronegativity difference between calcium and chlorine in CaCl2 is 1.0. The bond will be ionic. (c)
1. The electronegativity difference between nitrogen and fluorine in NF3 is 0.9. The bond will be polar covalent. (d)
2. The electronegativity difference between fluorine and fluorine in F2 is 0. The bond will be nonpolar covalent. (e)
3. The electronegativity difference between calcium and chlorine in CaCl2 is 1.0. The bond will be ionic. (c)
1 answer