Calculate the density of 92.9 g of an isopropyl alcohol-water mixture (commercial rubbing alcohol) that has a volume of 93.8 mL. Be sure your answer has the correct number of significant figures.

Answer 1

To calculate the density of a substance, you can use the formula:

\[ \text{Density} = \frac{\text{mass}}{\text{volume}} \]

Given:

• Mass = 92.9 g
• Volume = 93.8 mL

Now, plug the values into the formula:

\[ \text{Density} = \frac{92.9 , \text{g}}{93.8 , \text{mL}} \approx 0.9893 , \text{g/mL} \]

Next, we need to determine the number of significant figures for the final answer. The mass (92.9 g) has three significant figures, and the volume (93.8 mL) also has three significant figures. Therefore, the result should be rounded to three significant figures.

Thus, the density of the isopropyl alcohol-water mixture is:

\[ \text{Density} \approx 0.989 , \text{g/mL} \]

Final answer: 0.989 g/mL.