calculate the delta Hf of c6h12o6 (s) from the following data:

Question

Delta H combustion= -2816 kj/mol
delta Hf of Co2 = -393.5 kj/mol
delta Hf= of H2 O= -285.9kj/mol

Answer 1

dH = delta H.
C12H22O11 + 12O2 ==> 12CO2 + 11H2O
dHrxn = (12*dHf CO2 + 11*dHf H2O) - (1*dHf C12H22O11)
Plug in the values and solve for dHf C12H22O11.